180t=15t^2

Solution for 180t=15t^2 equation:

180t=15t^2

We move all terms to the left:

180t-(15t^2)=0

determiningTheFunctionDomain
-15t^2+180t=0

a = -15; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·(-15)·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*-15}=\frac{-360}{-30}
=+12
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*-15}=\frac{0}{-30}
=0
$